Miracle Posted November 15, 2012 Posted November 15, 2012 Hi Everyone, Working on my Standard Size Virtual Pinball, i use a old Stern Galaxy. I want to provide force feedback using the original flip coil (because i have a small budget and i think it's more "accurate" than a industrial relay). Does someone allready heard about this ? I don't have the original Stern alimentation, only a standard PC alimentation (12v, 5v). Does is it ok to operate the coil ? Thanks Ced.
mameman Posted November 15, 2012 Posted November 15, 2012 No usually they would have run at like 50v. You could try using a 48v power supply, but you are going to need most likely relays between them and the ledwiz to protect it. PM me for any custom CNC needs. Find me on Facebook.. Xtreme Pinball or www.xtremepinball.com Ipad pinball cabinet iFlipper Here: See the Doctor Who build Here.... / See the Tron build Here.... / See the BattleStar Galactica build Here.... See the Big Bang Bar build Here.... / See the Twilight Zone build Here.... CNC Work Here.....
zebulon Posted November 16, 2012 Posted November 16, 2012 Depending on the coil, they run anywhere from 30v to 50v and mameman's right, you definitely need something other than the ledwiz supplying the power. I know so much about so little that I could teach you everything there is to know about nothing....
Miracle Posted January 12, 2014 Author Posted January 12, 2014 Hi, I dig up this thread just if someone can tell me how powerfull should be the alimentation ? Does a 150W alimentation is enougth ? Thanks.
zebulon Posted January 12, 2014 Posted January 12, 2014 Going to need some more information on your coils and power supply to determine that. There are 2 basic calculations that you have to do. To determine the power needed in watts you need to calculate P=I x E where P is the Power (watts), I is the Current (amps) and E is the Electromotive Force (Volts). To determine the current in the above calculation (I) you need to use Ohm's Law where E=I x R, E once again being Voltage, I being Current and R being Resistance (ohms). So we need to fill in the blanks: If we want to find the current, we'll need to calculate the value of I from Ohm's Law which means we need to rearrange the formula like so: I= E/R Assuming that you are using a 48v power supply, to finish the formula we need the resistance of the coil in ohms: Then we would have: I=48/? Once we have I we can then use the calculation for power P=IxE Which would be : P=?x48 That would give us the power needed for 1 coil, you then need to figure out how many coils may run at one time (Ptotal) and then add a safety margin of 25% or so to avoid blowing the power supply with a spike (the coils will have what is called an inrush current associated with them and will draw more power initially and then settle down). So Ptotal would be PxNumCoils +25% I know so much about so little that I could teach you everything there is to know about nothing....
BamBam Posted January 16, 2014 Posted January 16, 2014 Going to need some more information on your coils and power supply to determine that. There are 2 basic calculations that you have to do.To determine the power needed in watts you need to calculate P=I x E where P is the Power (watts), I is the Current (amps) and E is the Electromotive Force (Volts). To determine the current in the above calculation (I) you need to use Ohm's Law where E=I x R, E once again being Voltage, I being Current and R being Resistance (ohms). So we need to fill in the blanks: If we want to find the current, we'll need to calculate the value of I from Ohm's Law which means we need to rearrange the formula like so: I= E/R Assuming that you are using a 48v power supply, to finish the formula we need the resistance of the coil in ohms: Then we would have: I=48/? Once we have I we can then use the calculation for power P=IxE Which would be : P=?x48 That would give us the power needed for 1 coil, you then need to figure out how many coils may run at one time (Ptotal) and then add a safety margin of 25% or so to avoid blowing the power supply with a spike (the coils will have what is called an inrush current associated with them and will draw more power initially and then settle down). So Ptotal would be PxNumCoils +25% Excellent example. Thanks. I love this stuff man!
zebulon Posted January 16, 2014 Posted January 16, 2014 Thanks for reading it... I know so much about so little that I could teach you everything there is to know about nothing....
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