Miracle Posted November 15, 2012 Share Posted November 15, 2012 Hi Everyone, Working on my Standard Size Virtual Pinball, i use a old Stern Galaxy. I want to provide force feedback using the original flip coil (because i have a small budget and i think it's more "accurate" than a industrial relay). Does someone allready heard about this ? I don't have the original Stern alimentation, only a standard PC alimentation (12v, 5v). Does is it ok to operate the coil ? Thanks Ced. Link to comment Share on other sites More sharing options...
mameman Posted November 15, 2012 Share Posted November 15, 2012 No usually they would have run at like 50v. You could try using a 48v power supply, but you are going to need most likely relays between them and the ledwiz to protect it. Link to comment Share on other sites More sharing options...
zebulon Posted November 16, 2012 Share Posted November 16, 2012 Depending on the coil, they run anywhere from 30v to 50v and mameman's right, you definitely need something other than the ledwiz supplying the power. Link to comment Share on other sites More sharing options...
Miracle Posted January 12, 2014 Author Share Posted January 12, 2014 Hi, I dig up this thread just if someone can tell me how powerfull should be the alimentation ? Does a 150W alimentation is enougth ? Thanks. Link to comment Share on other sites More sharing options...
zebulon Posted January 12, 2014 Share Posted January 12, 2014 Going to need some more information on your coils and power supply to determine that. There are 2 basic calculations that you have to do. To determine the power needed in watts you need to calculate P=I x E where P is the Power (watts), I is the Current (amps) and E is the Electromotive Force (Volts). To determine the current in the above calculation (I) you need to use Ohm's Law where E=I x R, E once again being Voltage, I being Current and R being Resistance (ohms). So we need to fill in the blanks: If we want to find the current, we'll need to calculate the value of I from Ohm's Law which means we need to rearrange the formula like so: I= E/R Assuming that you are using a 48v power supply, to finish the formula we need the resistance of the coil in ohms: Then we would have: I=48/? Once we have I we can then use the calculation for power P=IxE Which would be : P=?x48 That would give us the power needed for 1 coil, you then need to figure out how many coils may run at one time (Ptotal) and then add a safety margin of 25% or so to avoid blowing the power supply with a spike (the coils will have what is called an inrush current associated with them and will draw more power initially and then settle down). So Ptotal would be PxNumCoils +25% Link to comment Share on other sites More sharing options...
BamBam Posted January 16, 2014 Share Posted January 16, 2014 Going to need some more information on your coils and power supply to determine that. There are 2 basic calculations that you have to do.To determine the power needed in watts you need to calculate P=I x E where P is the Power (watts), I is the Current (amps) and E is the Electromotive Force (Volts). To determine the current in the above calculation (I) you need to use Ohm's Law where E=I x R, E once again being Voltage, I being Current and R being Resistance (ohms). So we need to fill in the blanks: If we want to find the current, we'll need to calculate the value of I from Ohm's Law which means we need to rearrange the formula like so: I= E/R Assuming that you are using a 48v power supply, to finish the formula we need the resistance of the coil in ohms: Then we would have: I=48/? Once we have I we can then use the calculation for power P=IxE Which would be : P=?x48 That would give us the power needed for 1 coil, you then need to figure out how many coils may run at one time (Ptotal) and then add a safety margin of 25% or so to avoid blowing the power supply with a spike (the coils will have what is called an inrush current associated with them and will draw more power initially and then settle down). So Ptotal would be PxNumCoils +25% Excellent example. Thanks. Link to comment Share on other sites More sharing options...
zebulon Posted January 16, 2014 Share Posted January 16, 2014 Thanks for reading it... Link to comment Share on other sites More sharing options...
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